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Copper Lab
Friday, December 18, 2009
CuCl2 + Na3(PO4)2 -----> Cu3(PO4)2 + NaCl
Here is colby getting low to make precise measurmenrts.
Involves a reaction between the cupric- chloride solution and a solution of sodium phosphate to produce a blue cupric phosphate and sodium chloride.
This is a double replacement, because the Cu reacted with the PO4 and the Na reacted with the Cl.
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CuSO4 +Zn -----> Cu + 2ZnSO4
Cu3(PO4)2 + 3H2SO4 -----> 3CuSO4 + 2H3PO4
CuCl2 + Na3(PO4)2 -----> Cu3(PO4)2 + NaCl
CuO + 2HCl -----> CuCL2 + H2O
Cu(NO3) -----> Cu + 2H2O
2Cu(NO3)2 + 4NaOH -----> 2Cu(OH)2 + 4NaNO3
Cu + 4HNO3 ----> Cu(NO3)2 + 2H2O + 2NO2
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