Friday, December 18, 2009

CuCl2 + Na3(PO4)2 -----> Cu3(PO4)2 + NaCl

Here is colby getting low to make precise measurmenrts.

Involves a reaction between the cupric- chloride solution and a solution of sodium phosphate to produce a blue cupric phosphate and sodium chloride.
This is a double replacement, because the Cu reacted with the PO4 and the Na reacted with the Cl.

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